Question

For this PreLab assignment we will assume all of the acid is the monoprotic acid acetylsalicylic acid (C9H8O4). [Note: for your analysis in the PostLab you will subtract the moles of salicylic acid from the total acid content to determine the amount of acetylsalicylic acid]. How many moles of acetylsalicylic acid are in the 0.2001 g sample of your aspirin

Answer 1

There are approximately 0.0011 moles of acetylsalicylic acid in the 0.2001 g sample of aspirin.

Step-by-step explanation:

To determine the number of moles of acetylsalicylic acid (C9H8O4) in a 0.2001 g sample of aspirin, we need to use the molar mass of acetylsalicylic acid. The molar mass of acetylsalicylic acid is 180.2 g/mol.

To calculate the number of moles, we use the formula:

moles = mass / molar mass

So, moles = 0.2001 g / 180.2 g/mol = 0.0011095 mol.

Therefore, there are approximately 0.0011 moles of acetylsalicylic acid in the 0.2001 g sample of aspirin.

Answer 2

0.0011 moles

Step-by-step explanation:

Recall that;

Number of moles = mass of substance/ molar mass of the substance

Mass of asprin = 0.2001 g

Molar mass of asprin = 180.158 g/mol

Number of moles = 0.2001 g/180.158 g/mol

Number of moles = 0.0011 moles