Answer:
The answer is "60 msec".
Step-by-step explanation:
The first RTT sends a segment (or 4KB) for a slow start. Its second RTT dispatch two segments (or 8KB), the third four (or 16KB) segments, its fourth 8 segments (or 32KB) Now if it could only enhance information in linear terms (not exponential rate), it can only add 1 MSS that would be 4KB (5th RTT) and another 4KB (6th RTT), which would be total of 60 msec.