Question

1. Priya is responsible for collecting canned food along three different streets for her school's

annual Thanksgiving Food
Drive. She walks 300 m [N] along Oak Road, 500 m [E] along
Second Street, and then 150 m (S45°W) along Cross Ave. She completes the journey in 10
minutes
a. Draw a scale diagram of her trip.
b. Calculate her total distance, displacement, speed, and velocity.

Answer 1

distance = 950 m

displacement = 439.2 m

speed= 1.58 m/s

velocity = 0.732 m/s

Step-by-step explanation:

A = 300 m North

B = 500 m East

C = 150 m South west

Time, t = 10 minutes = 600 s

(A) The diagram is given below.

(B) Total distance = 300+ 500 + 150 = 950 m

`A = 300 \widehat{j} \\\\B = 500\widehat{i}\\\\C = - 150 (cos 45 i+ sin 45 j) = - 106 \widehat{i} - 106 \widehat{j}\\\\D = A + B + C \\\\D = 394 \widehat{i} + 194 \widehat{j}\\\\D=√(394^2 +194^2) = 439.2 m`

Speed = distance / time = 950/600 = 1.58 m/s

velocity = 439.2 / 600 = 0.732 m/s