Question

I need step by step answers pleasseeee
Systems of Equations
4x-3y=-20
-x-8y=5

Answer 1

x = -5

y = 0

Explanation:

4x-3y=-20

-x-8y=5 then x = 8y-5

substitute for x

4(8y-5)-3y = -20

32y-20-3y = -20

29y = 0

y = 0

4x-0 = -20

x = -5

Answer 2

(-5, 0)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Distributive Property

Equality Properties

• Multiplication Property of Equality
• Division Property of Equality
• Addition Property of Equality
• Subtraction Property of Equality

Algebra I

• Terms/Coefficients
• Coordinates (x, y)
• Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define Systems

4x - 3y = -20

-x - 8y = 5

Step 2: Rewrite Systems

-x - 8y = 5

1. [Addition Property of Equality] Add 8y on both sides: -x = 8y + 5
2. [Division Property of Equality] Divide -1 on both sides: x = -8y - 5

Step 3: Redefine Systems

4x - 3y = -20

x = -8y - 5

Step 4: Solve for y

Substitution

1. Substitute in x: 4(-8y - 5) - 3y = -20
2. [Distributive Property] Distribute 4: -32y - 20 - 3y = -20
3. Combine like terms: -35y - 20 = -20
4. [Addition Property of Equality] Add 20 on both sides: -35y = 0
5. [Division Property of Equality] Divide -35 on both sides: y = 0

Step 5: Solve for x

1. Define original equation: -x - 8y = 5
2. Substitute in y: -x - 8(0) = 5
3. Multiply: -x = 5
4. [Division Property of Equality] Divide -1 on both sides: x = -5