314,407 views
5 votes
5 votes
Hiệu điện thế giữa hai điểm M và N là UMN = 100 V. Một điện tích q = -2μC di chuyển từ M đến N thì công của lực điện là:

User Shane Scott
by
3.1k points

1 Answer

23 votes
23 votes

Answer:

The work done is - 200 μJ.

Explanation:

The potential difference between two points M and N is UMN = 100 V. A charge q = -2μC moves from M to N, the work of the electric force is:

Potential difference, V = 100 V

Charge, q = - 2 μC

The potential difference is defined as the amount of work done in bringing a unit positive test charge from one point to another in the electric field.

So, W = q V

W = - 2 μC x 100 V = - 200 μJ

User Stijn Bernards
by
3.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.