Answer:
the resistance of the second wire is 1 ohm.
Step-by-step explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝

Since the length of the two wires is constant
R₁A₁ = R₂A₂

Therefore, the resistance of the second wire is 1 ohm.