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A rock is thrown straight up with an initial velocity of 25.0 m/s. What maximum height will the rock reach before starting to fall downward

1 Answer

10 votes

Answer:

31,86m

Step-by-step explanation:

mgh=(mv^2)/2

gh=v^2/2

h=v^2/2g

h=25^2/2*9 81

h=31,86m

User Ankit Chaudhary
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