Question

A 10cm long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.35 Ω. Pulling the wire with a force of 1.0 N causes 4.0 W of power to be dissipated in the circuit.

a. What is the speed of the wire when pulled with a force of 1.0 N?
b. What is the strength of the magnetic field?

Answer 1

a)
`v=4.0m/s`

b)
`B=2.958T`

Step-by-step explanation:

From the question we are told that:

Wire Length
`l=10cm=>0.10m`

Resistance
`R=0.35`

Force
`F=1.0N`

Power
`P=4.0W`

a)

Generally the equation for Power is mathematically given by

`P=Fv`

Therefore

`v=(P)/(F)`

`v=(4.0)/(1.0)`

`v=4.0m/s`

b)

Generally the equation for Magnetic Field is mathematically given by

`B=(√(PR))/(vl)`

`B=(√(4*0.35))/(4*0.10)`

`B=2.958T`