Question

In the perfect square x^2+bx+c, why is the relationship between b and c C=(b/2)^2? Would the strategy work even if b is a negative? Also, would it work if b was an odd number? What would happen to c if b was odd?

Answer 1

Explanation:

c = (b/2)² because b = 2c

If b is negative, then c = (-b/2)² , and x² - bx + c = (x-c)²

If b is an odd number, then c will be a fraction.