191k views
3 votes
I have been struggling with this for a while lol​

I have been struggling with this for a while lol​-example-1

1 Answer

6 votes

Answer:

f(x) = (3x -2)(2x +1)

Explanation:

The procedure for factoring expression of the form ...

ax² +bx +c

is to look for factors of a·c that have a sum of b.

The product a·c is 6·(-2) = -12. You are looking for factors that have a sum of b = -1. From your familiarity with multiplication tables, you know ...

-12 = 1(-12) = 2(-6) = 3(-4)

The sums of the factor pairs in this list are -11, -4, -1. So, the last pair of factors, {3, -4} is the one we're looking for.

__

At this point, there are several ways to proceed. Perhaps the simplest is to rewrite the linear term as the sum of terms involving these factors:

-x = 3x -4x

f(x) = 6x² +3x -4x -2

Now, the expression can be factored 2 terms at a time:

f(x) = (6x² +3x) -(4x +2) . . . . . pay attention to signs

f(x) = 3x(2x +1) -2(2x +1) . . . . factor each pair

f(x) = (3x -2)(2x +1) . . . . . . . . factor out the common factor of (2x+1)

User Zeeali
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories