Question

Determine the mass in grams of 3.75 x 10^21 atoms of zinc. (the mass of one mole of zinc is 65.39 g)

Answer 1

3.50 g

Step-by-step explanation:

multiply (3.75•10^21) • (6.022•10^23)

Then divide that answer by (65.39)

Round and keep 3 significant figures.

Answer 2

Answer: The mass in
`3.75 * 10^(21)` atoms of zinc is 0.405 g.

Step-by-step explanation:

Given: Atoms of zinc =
`3.75 * 10^(21)`

It is known that 1 mole of every substance contains
`6.022 * 10^(23)` atoms. So, the number of moles in given number of atoms is as follows.

`Moles = (3.75 * 10^(21))/(6.022 * 10^(23))\\= 0.622 * 10^(-2)\\= 0.0062 mol`

As moles is the mass of a substance divided by its molar mass. So, mass of zinc (molar mass = 65.39 g/mol) is calculated as follows.

`Moles = (mass)/(molar mass)\\0.0062 mol = (mass)/(65.39 g)\\mass = 0.405 g`

Thus, we can conclude that the mass in
`3.75 * 10^(21)` atoms of zinc is 0.405 g.