Question

How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

Answer 1

1.3 moles/ 1.33150727 moles

Step-by-step explanation:

350g x 1 mol/262.86g = 1.3 moles

Answer 2

The molar mass of Mg3(PO4)2 is 262.855 g/mol

Atomic weight of the parts:

Mg 24.3050 x 3 = 72.92

P 30.973762 x2 = 61.95

O 15.9994 x8 = 127.995

There are 262.855 grams in one mole, so

350.00 g x (262.855g/1 mole) = 1.33 moles Mg3(PO4)2