Question

How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?

Answer 1

To find the number of atoms of boron in 3.61 grams of boron trifluoride, divide the given mass by the molar mass of boron and then multiply by Avogadro's number.

Step-by-step explanation:

To find the number of atoms of boron in 3.61 grams of boron trifluoride (BF3), we need to use the concept of mole and Avogadro's number. The molar mass of boron is 10.81 g/mol, so we need to divide the given mass by the molar mass to find the number of moles of boron. Then, we multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms of boron.

First, we calculate the number of moles of boron:
Number of moles = Mass / Molar mass = 3.61 g / 10.81 g/mol = 0.334 mol

Next, we calculate the number of atoms of boron:
Number of atoms = Number of moles * Avogadro's number = 0.334 mol * (6.022 x 10^23 atoms/mol) = 2.01 x 10^23 atoms

Answer 2

Hi there!

`\large\boxed{3.203 * 10^(22) atoms}`

We can use the following conversions to solve:

Total mass --> amount of mols --> amount of atoms (Avogadro's number)

Begin by calculating the amount of boron trifluoride in 3.61 grams:

3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃

Use avogadro's number to convert:

0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms