Answer:
(a) 7.1
(b) (5/2, 3/2)
(c) 2
(d) y = -x +4
Explanation:
(a)
The length of AC is found using the distance formula:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((5 -(-2))² +(-1 -0)²) = √(49 +1) = 5√2 ≈ 7.1
The length of AC is about 7.1.
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(b)
The midpoint has coordinates that are the average of the end point coordinates.
midpoint BC = (B + C)/2 = ((0, 4) +(5, -1))/2 = (5, 3)/2
midpoint BC = (5/2, 3/2)
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(c)
The slope is found using the slope formula.
m = (y2 -y1)/(x2 -x1)
For points A(-2, 0) and B(0, 4), the slope of the segment between them is ...
m = (4 -0)/(0 -(-2)) = 4/2 = 2
The slope of AB is 2.
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(d)
The slope of line BC is found in the same was as for AB.
m = (-1 -4)/(5 -0) = -5/5 = -1
The y-intercept of the line is point B, at y=4. So, the equation of line BC is ...
y = mx +b . . . . . where m is the slope, and b is the y-intercept
y = -x +4