Answer:
a) the rate at which 235U is fissioned is 2895.9 grams per day
b) the rate at which 235U is consumed is 3385.3071 gram/day
Step-by-step explanation:
Given the data in the question;
a)
designed operation thermal power = 2758 MW.
we know that, the burn up rate fission rate of 235U is 1.05 grams per MW-day.
so, the rate at which 235U is fissioned will be;
⇒ 2758 × 1.05 = 2895.9 grams per day
Therefore, the rate at which 235U is fissioned is 2895.9 grams per day
b)
Consumption rate is given as;
Cr = 1.05 × ( 1 + ∝ )P gram/day
where ∝ is 0.169 for U-235
so,
Cr = 1.05 × ( 1 + 0.169 )2758 gram/day
Cr = 1.05 × 1.169 × 2758 gram/day
Cr = 3385.3071 gram/day
Therefore, the rate at which 235U is consumed is 3385.3071 gram/day