Question

Someone please help me I’m literally struggling

Answer 1

The first question will be 3x to the power of 3
The second one will 2
The third will substitute a and put 3x and substitute b and but 2

Answer 2

Hello,

We have :

27 = 3³ = 3 × 3 × 3

`x`³ =
`x` ×
`x` ×
`x`

So :

The cube root of 27
`x`³ is :

3 ×
`x` = 3
`x`

( because : (3
`x`)³ = 27
`x`³ )

We have :

8 = 2³ = 2 × 2 × 2

So :

The cube root of 8 is : 2

`a^(3) +b^(3) = (a+b)(a^(2) -ab+b^(2) )` with
`a=3x` and
`b=2`

We have :

`(3x)^(3)+2^(3)=(3x+2)((3x)^(2) -(3x)(2)+(2 )^(2) )`

Have a nice day :)