Question

A box slides down a 28.0 degree ramp with an acceleration of 1.25 m/s2. Determine the coefficient of kinetic friction between

Answer 1

`\mu=0.39`

Step-by-step explanation:

From the question we are told that:

Angle
`\theta=28`

Acceleration
`a=1.25m/s^2`

Generally the equation for Frictional force is mathematically given by

`F=\muN`

Where

`N=mgcos \theta`

`N=mgcos 28`

Since

Friction force is acting against move of box

Therefore

`mgsin(28) - 1.25m = \mu mgcos(28)`

`\mu=(gsin(28) - 1.25)/(gcos(28))`

`\mu=0.39`