Question

1). What is the equation of the line that is perpendicular to y= -3x+1 that passes through the point (9,0)?

2). What is the equation of the line that is parallel to y= -3x+1 that passes through the point (9,0)?



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Answer 1

Explanation:

1) Slope of the given line = -3

slope of the perpendicular line = 1/3

y - 0 = 1/3(x-9)

y = 1/3x - 3

2) slope of the parallel line = -3

y - 0 = -3(x-9)

y = -3x + 27

Answer 2

1). y = 1/3x - 3 2).y = -3x + 27

Explanation:

1). y = 1/3x + b

0 = 1/3(9) + b

0 = 3 + b

-3 = b

y = 1/3x - 3

2)/ y = -3x + b

0 = -3(9) + b

0 = -27 + b

27 = b

y = -3x + 27