Question

3 years later a mother will be 4 times as

old as her son. 3 years ago ,the mother age was two times as old as her son age will be 8 years hence. What are their present ages?​

Answer 1

• 33 and 6 years

Explanation:

• Mother's age = m
• Son's age = s

3 years later:

• m + 3 = 4(s + 3) ⇒ m = 4s + 12 - 3 = 4s + 9

3 years ago:

• m - 3 = 2(s + 8) ⇒ m = 2s + 18 + 3 = 2s + 21

Solve for s by substitution:

• 4s + 9 = 2s + 21
• 2s = 12
• s = 6

Find the value of m:

• m = 4*6 + 9 = 33

Mother is 33 and son is 6