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43 votes
43 votes
The width of a rectangular lot is 100 feet less than the length. If the perimeter is 1000 feet, what

are the dimensions of the lot?

User David Lemphers
by
2.9k points

2 Answers

20 votes
20 votes

Answer:

  • W = 200 ft.
  • L = 300 ft.

Explanation:

We know that:

  • W = L - 100
  • P = 1000 feet

Solution:

  • P = 1000 feet
  • => L + W + L + W = 1000 ft.
  • => L + L - 100 + L + L - 100 = 1000 ft.
  • => 4L - 200 = 1000 ft.
  • => 4L = 1200 ft.
  • => L = 300 ft.
  • => W = L - 100
  • => W = 300 - 100
  • => W = 200 ft.

Hence, the length and the width of the rectangular lot is 300 ft. and 200 ft. respectively.

User Juan De La Cruz
by
2.7k points
13 votes
13 votes

Answer:

length = 300 feet , width = 200 feet

Explanation:

Let the length of the lot be x feet

Then the width shall be ( x - 100 ) feet

  • perimeter of rectangle formula: 2 ( length + width )

1000 : 2 ( x + x - 100 )

1000 : 2 ( 2x - 100 )

1000 : 4x - 200

1000 + 200 : 4x

x : 1200 / 4

x : 300

Then the length is 300 feet

The width is ( x -100 ) = 300 - 100 = 200 feet

User Yang Zhao
by
3.4k points