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The width of a rectangular lot is 100 feet less than the length. If the perimeter is 1000 feet, what

are the dimensions of the lot?

User Tomet
by
8.9k points

2 Answers

9 votes

Answer:

  • W = 200 ft.
  • L = 300 ft.

Explanation:

We know that:

  • W = L - 100
  • P = 1000 feet

Solution:

  • P = 1000 feet
  • => L + W + L + W = 1000 ft.
  • => L + L - 100 + L + L - 100 = 1000 ft.
  • => 4L - 200 = 1000 ft.
  • => 4L = 1200 ft.
  • => L = 300 ft.
  • => W = L - 100
  • => W = 300 - 100
  • => W = 200 ft.

Hence, the length and the width of the rectangular lot is 300 ft. and 200 ft. respectively.

User Voltrevo
by
8.4k points
9 votes

Answer:

length = 300 feet , width = 200 feet

Explanation:

Let the length of the lot be x feet

Then the width shall be ( x - 100 ) feet

  • perimeter of rectangle formula: 2 ( length + width )

1000 : 2 ( x + x - 100 )

1000 : 2 ( 2x - 100 )

1000 : 4x - 200

1000 + 200 : 4x

x : 1200 / 4

x : 300

Then the length is 300 feet

The width is ( x -100 ) = 300 - 100 = 200 feet

User MrRobboto
by
7.8k points

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