Answer:
Simplify 32(x^2+4x)
32x^2+128x=16(x^2+4x+3)
simplify 16(x^2+4x+3)
32x^2+128x=16x^2+64x+48
subtract 16x^2 from both sides
subtract 64x from both sides
subtract 16x^2 and 32x^2
subtract 64x from 128x
x=−2+√7,−2−√7 answer
hope this helps :))
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