Question

write the slope-intercept form of the equation of the line that passes through the point (-4,-1) and is parallel to the line y=3/4x-1

Answer 1

Explanation:

Parallel lines have same slope.

y= mx + b

Slope = m & b = y-intercept

y = 3/4 x - 1

m = 3/4 ; (-4 , -1)

y - y1 = m(x - x1)

`y - [-1]=(3)/(4)(x -[-4])\\\\y + 1 = (3)/(4)(x+4)\\\\y +1 = (3)/(4)*x + 4*(3)/(4)\\\\y + 1 = (3)/(4)x+3\\\\y =(3)/(4)x+3-1\\\\y =(3)/(4)x+2`