A sample of 41.9 g of aluminum is reacted with
67.2 g of chlorine gas to produce aluminum
trichloride. Using the balanced equation below,
predict which is the limiting reactant and the
maximum amount in moles of aluminum trichloride
that can be produced.
2A1 + 3Cl2 + 2AlCl3
A. aluminum, 1.55 moles
B. chlorine gas, 0.632 moles
C. aluminum, 0.865 moles
D. chlorine gas, 0.954 moles