Final answer:
In the reaction to form diethyl ether from ethyl alcohol and ethyl bromide, the electrophilic site is the carbon attached to the bromine in ethyl bromide, while the nucleophilic site is the oxygen in ethyl alcohol. Ethyl alcohol attacks ethyl bromide, leading to diethyl ether formation after deprotonation.
Step-by-step explanation:
The reaction between ethyl alcohol (ethanol) and ethyl bromide (an alkyl halide) to form diethyl ether is a two-step process that involves a substitution reaction followed by deprotonation. In this process, the electrophilic site is the carbon atom bonded to the bromine atom in ethyl bromide, as it carries a partial positive charge due to the polar C-Br bond. The nucleophilic site is the lone pair of electrons on the oxygen atom of ethyl alcohol, which can donate electrons to form a new covalent bond.
Initially, ethyl alcohol acts as a nucleophile and attacks the electrophilic carbon of ethyl bromide, leading to the formation of an ether linkage and a bromide ion. This initial addition reaction is followed by the deprotonation of the protonated ether to give diethyl ether.
When considering Alkyl halides, these can be produced from alkenes through electrophilic addition reactions, such as the addition of bromine to ethene, resulting in a disubstituted alkyl halide. Similarly, reactions of ethers typically involve the protonation of the ether oxygen to transform it into a good leaving group, followed by nucleophilic substitution reactions.
In the context of various organic reactions, identifying the nucleophilic and electrophilic sites is crucial to understanding how molecules interact and the outcomes of their reactions. For example, an O-methylation reaction involves the oxygen of an alcohol acting as a nucleophile, replacing the iodide in methyl iodide, which is a very good leaving group.