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What are the roots of 0=9x^2-49

User Annelise
by
8.5k points

2 Answers

2 votes

Answer:

x=-7/3, 7/3.

Explanation:

0=9x^2-49

9x^2-49=0

factor

(3x+7)(3x-7)=0

3x+7=0, 3x-7=0

3x=0-7, 3x=-7, x=-7/3

3x=0+7, 3x=7, x=7/3

User Akash Raghav
by
7.7k points
10 votes

7/3 or -7/3

Explanation:

User AlexJReid
by
7.8k points

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