Register

What are the roots of 0=9x^2-49

What are the roots of 0=9x^2-49
57.4k views
13 votes
What are the roots of 0=9x^2-49

User Annelise
by
8.5k points

2 Answers

2 votes

Answer:

x=-7/3, 7/3.

Explanation:

0=9x^2-49

9x^2-49=0

factor

(3x+7)(3x-7)=0

3x+7=0, 3x-7=0

3x=0-7, 3x=-7, x=-7/3

3x=0+7, 3x=7, x=7/3

User Akash Raghav
by
7.7k points
10 votes

7/3 or -7/3

Explanation:

User AlexJReid
by
7.8k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!