Answer:
218.7 mL
Step-by-step explanation:
The reaction that takes place is:
- HCOOH + LiOH → LiCOOH + H₂O
First we calculate how many HCOOH moles reacted, using the given volume and concentration:
- 82.0 mL * 0.400 M = 32.8 mmol HCOOH
As 1 HCOOH mol reacts with 1 LiOH mol, 32.8 mmoles of LiOH are needed to react with 32.8 mmoles of HCOOH.
Finally we calculate how many mL of a 0.150 M solution would contain 32.8 mmoles:
- 32.8 mmol / 0.150 M = 218.7 mL