Question

How much work is required to stretch an ideal spring of spring constant (force constant) 40 N/m from x

Answer 1

The work done will be "0.45 J".

Step-by-step explanation:

Given:

K = 40 N/m

x₁ = 0.20 m

x₂ = 0.25 m

Now,

The required work done will be:

=
`(1)/(2)k[x_2^2-x_1]`

By putting the values, we get

=
`(40)/(2)[(0.25)^2-(0.20)^2]`

=
`20* 0.0225`

=
`0.45 \ J`