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What is 8x + 10 ≤ 51 please show work

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\huge\fbox{Hi~there!~:)}

Let's solve this inequality! :)

Let's start by subtracting 10 from both sides:


\rm{8x\leq 51-10}


\rm{8x\leq 41

Now, divide both sides by 8:


x\leq \displaystyle(41)/(8) (Answer)

Decimal form:


\rm{5.125}

I hope you find it helpful.

Feel free to ask if you have any doubts.


\bf{-MistySparkles^**^* here to help

User Pawan Dongol
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