Question

A chemist determines by measurements that 0.0800 moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates. Round your answer to 3 significant digits.

Answer 1

The mass of bromine liquid that participates in a chemical reaction=12.8 g

Step-by-step explanation:

We are given that

Total number of moles of bromine liquid participate in chemical reaction=0.0800 moles

We have to find the mass of bromine liquid that participates.

Atomic mass of Br=79.9 g

1 mole of bromine liquid=2 atomic mass of bromine (Br)

1 mole of bromine liquid (
`Br_2`) =
`2* 79.9=159.8 g`

0.0800 moles of bromine liquid=
`159.8* 0.0800` g

0.0800 moles of bromine liquid=12.784 g

0.0800 moles of bromine liquid
`\approx 12.8` g

Hence, the mass of bromine liquid that participates in a chemical reaction=12.8 g