Answer:
g' (×)=f
Explanation:
g (×)=f×-7
g' (×)= d÷d× (f×-7)
d÷d×(f+g)=d÷d×(f)+d÷d=(g)
g' (×)=d÷d×(f×)-d÷d×(7)
g'(×)=f-d÷d×(7)
g'(×)=f-0
g'(×)=f
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