Question

three condensers are connected in series across a 150 volt supply. The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10^-8(a) calculate the capacitance of each condenser (b)calculate the effective capacitance of the combination

Answer 1

Step-by-step explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

`C_1=(Q)/(V_1)\\\\C_1=(6* 10^(-8))/(40)\\\\C_1=1.5* 10^(-9)\ F\\\\C_1=1.5\ nF`

Capacitance of capacitor 2,

`C_2=(Q)/(V_2)\\\\C_2=(6* 10^(-8))/(50)\\\\C_2=1.2* 10^(-9)\ F\\\\C_2=1.2\ nF`

Capacitance of capacitor 3,

`C_3=(Q)/(V_3)\\\\C_3=(6* 10^(-8))/(60)\\\\C_3=1* 10^(-9)\ F\\\\C_3=1\ nF`

(b) The equivalent capacitance in series combination is :

`(1)/(C)=(1)/(C_1)+(1)/(C_2)+(1)/(C_3)\\\\(1)/(C)=(1)/(1.5)+(1)/(1.2)+(1)/(1)\\\\C=0.4\ nF`

Hence, this is the required solution.