Question

A boy is moving a stone in a horizontal circle by mean of a thread attached to ut. The length if the threads us 1 m and the weight of the stone is 0.02 kg . The maximum tension of the thread can withstand us 1 ×10 ^-4 N. The boy is gradually increasing the speed if rotation. At what speed if the stone does the thread break ? ​

Answer 1

Step-by-step explanation:

This is a centripetal force problem where tension supplies the centripetal force needed to keep the stone moving in a circular manner. That formula for that is

`F_c=T=(mv^2)/(r)` and filling in what we know:

`1*10^(-4)=(.02v^2)/(1)` and solve that for v:

`v=\sqrt{(1*10^(-4))/(.02) }` which gives us a velocity of .07 m/s. Anything greater than this will break the string.