Answer:
E) y= 2x-11
Explanation:
as we know the equation of line parallel to
y =2x-7 or, 2x-y-7=0 is 2x-y+k=0
as the line passes through the point (5,-1)
substituting the value of x and y in equation 2x-y+k=0
we get,
2×5-(-1)+k=0
or, 10+1+k=0
or, k=-11
hence putting the value of k in ep 2x-y+k=0
we get 2x-y-11=0
or, y=2x-11