Answer:
Explanation:
They already said the domain of f(x) is x≥0.
The smallest value of f(x) is f(0) = 9.
Range of f(x) is y≥9.
The radicand of a square root must be non-negative, so the domain of f⁻¹(x) is x≥9.
The range is y≥0.
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