Question

The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part to 80 dB during a loud part. Approximately how many times louder is the latter sound

Answer 1

`\alpha=-3.01dB`

Step-by-step explanation:

From the question we are told that:

Sound level intensity

`\triangle I=40dB-80dB`

Generally the equation for intensity level is mathematically given by

`\alpha=10log_(10)(I/I_x)dB`

Where

I= Intensity measured

`I_x=Threshold\ of\ audibility`

`I_x= 10-12 W / m2`

`\alpha= 10 log10 (I_1)/(I_x) - 10 log10 \frac{}I_2{I_x}`

`\alpha= 10 log10 (I_1)/(I_2)`

`\alpha=10 log10(40)/(80)`

`\alpha=-3.01dB`