Question

A cable is lifting a construction worker and a crate, as the drawing shows. The weights of the worker and crate are 965 and 1510 N, respectively. The acceleration of the cable is 0.620 m s 2 , upward. What is the tension in the cable (a) below the worker and ( b) above the worker

Answer 1

Step-by-step explanation:

a)

Below the worker , the tension in cable is pulling the crate . Let the tension be T₁ .

weight of crate is acting downwards .

Total weight 1510 N.

Net force acting on both = T₁ - 1510

Applying second law of Newton ,

T₁ - 1510 = 1510 / 9.8 x 0.62 [ 1510 / 9.8 = mass of crate ]

T₁ - 1510 = 95.5

T₁ = 1605.5 N.

b )

Above the worker , the tension in cable is pulling both the worker and the crate . Let the tension be T₂ .

weight of both worker and crate is acting downwards .

Total weight = 965 + 1510 = 2475 N.

Net force acting on both = T₂ - 2475

Applying second law of Newton ,

T₂ - 2475 = 2475 / 9.8 x 0.62 [ 2475 / 9.8 = mass of both worker and crate ]

T₂ - 2475 = 156.6

T₂ = 2631.6 N.