Answer:
L = 96,4 10³ m
Step-by-step explanation:
After reading this long statement of the problem, we can approximate the well as a tu with one end open and the other end closed, therefore we have two resonance frequencies.
The resonance at the open ends forms a maximum and at the closed ends a node is formed, therefore the standing wave fulfills the relationship
L = λ/ 4 1st harmonic
L = 3 λ/4 3rd harmonic
L = 5 λ/4 5rd harmonic
therefore the general term is
L = n λ/ 4 n = 1, 3, 5, 7 .. (2n + 1)
The speed of sound is related to the donut length and the frequencies
v = λ f
λ = 4L / n
v =
as the speed of sound is a constant
for the initial frequency f = 54 Hz occurs for the number n
340 =
L / n =
L / n = 4590
for the frequency f = 59.68 Hz it has an odd number n
340 =
L / n '=
L / n '= 5072.8
we have a system of two unknowns with two equations
L / n = 4590
L / n '= 5072.8
therefore the length is
L = 4590 n = 5072.8 n '
as the two frequencies are very close we can assume that they correspond to consecutive odd numbers
n = 1.1052 n '
n n’ n’ / n
1 3 3
3 5 1.66
5 7 1.4
7 9 1,286
9 11 1.22
11 13 1.18
13 15 1.15
15 17 1.13
17 19 1,117
19 21 1.1052
We can see in the table the two numbers must be n = 19 and n ’= 21
let's calculate the length of the well
L = 4590 21
L = 96390 m
L = 96,4 10³ m