Answer:
Step-by-step explanation:
Given that:
At the inlet:
Temperature
![T_1 = 25^0 \ C](https://img.qammunity.org/2022/formulas/physics/college/ih5abro3gcgb16qgp3is19juthj0kedn7k.png)
Pressure
= 20bar = 2000 kPa
At the outlet:
![P_2 = 2000 \ kPa](https://img.qammunity.org/2022/formulas/physics/college/nlm191ct2jtzdjo13i10jaepyuj873m5uq.png)
a)
Q = 500 kJ/kg
Using the steam tables to determine the properties of water;
![h_1 = 106.6863 \ kJ/kg \\ \\ h_2 -h_1 = 500 \\ \\ h_2 = (500 + 106.6863) \ kJ/kg \\ \\ h_2 = 606.68 \ kJ/kg](https://img.qammunity.org/2022/formulas/physics/college/fzl4zgg95ivgd2qfwaplf6h6p3kjeu0qr2.png)
![at \ p_(sat)= 2000 \ kPa; \ h_f = 908.47 \kJ/kg; \ h_g = 2798.3 \ kJ/kg} \\ \\ h_2< h_f; \text{thus, the soil is compressed or subcooled liquid}](https://img.qammunity.org/2022/formulas/physics/college/k1ol6egds7wjqm5x0flrw13edsc95gcp4c.png)
b)
![Q = 1500 \ kJ/kg\\ \\ Q= (h_2-h_1) \\ \\ h_2 = 1500 + 106.6863 \\ \\ h_2 = 1606.6863 \ kJ/kg \\ \\ h_f < h_2<hg \ at \ 2000 \ kPa](https://img.qammunity.org/2022/formulas/physics/college/jr0n4qf7uf1rdeqht8wkkva6m3mubgvgx9.png)
Thus, the outlet steam will be a vapor-liquid mixture at 212.38° C
c)
![Q = 3000 \ kJ/kg \\ \\ Q = h_2 -h_1 \\ \\ h_2 = Q + h_1 \\ \\ h_2 = 3000 + 106.6863 \\ \\ h_2 = 3106.6863 \ kJ/kg\\ \\ h_2 > hg \ at \ 2000 \ kPa](https://img.qammunity.org/2022/formulas/physics/college/g48ae9gukkqxgc8uli2nab3b1x7odj7yvi.png)
Thus, the outlet steam will be a superheated vapor at 380° C