Answer: A mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.
Step-by-step explanation:
Given: Volume = 450 L
Temperature = 450 K
Pressure = 300 atm
Using ideal gas equation, moles of nitrogen are calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = tempertaure
Substitute values into the above formula as follows.
![PV = nRT\\300 atm * 450 L = n * 0.0821 L atm/mol K * 450 K\\n = (135000)/(36.945)\\= 3654.08 mol](https://img.qammunity.org/qa-images/2022/formulas/chemistry/high-school/y5rmgtrjafupl1bhve6g6r.png)
According to the given equation, 1 mole of nitrogen forms 2 moles of ammonia. So, moles of ammonia formed by 3654.08 moles of nitrogen is as follows.
![2 * 3654.08 mol\\= 7308.16 mol](https://img.qammunity.org/qa-images/2022/formulas/chemistry/high-school/wtoksc748ascwjoayf7ifz.png)
As moles is the mass of substance divided by its molar mass. So, mass of ammonia (molar mass = 17.03 g/mol) is as follows.
![Moles = (mass)/(molar mass)\\7308.16 = (mass)/(17.03 g/mol)\\mass = 124457.96 g](https://img.qammunity.org/qa-images/2022/formulas/chemistry/high-school/joxrbqel48po6oww5qh0r7.png)
Thus, we can conclude that a mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.