Question

Three 15-Ω and two 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes through each bulb?

1) 0.18 A
2) 0.25 A
3) 0.51 A
4) 0.74 A
5) The current will be 1.6 A in the 15-Ω bulbs and 0.96 A in the 25-Ω bulbs.

Answer 1

I = 0.25 A

Step-by-step explanation:

Given that,

Three 15 ohms and two 25 ohms light bulbs and a 24 V battery are connected in a series circuit.

In series combination, the equivalent resistance is given by :

`R=R_1+R_2+R_3+....`

So,

`R=15+15+15+25+25\\\\=95\ \Omega`

The current each resistor remains the same in series combination. It can be calculated using Ohm's law i.e.

V = IR

`I=(V)/(R)\\\\I=(24)/(95)\\\\I=0.25\ A`

So, the current of 0.25 A passes through each bulb.