Register
Two charged particles exert an electric force of 27 N on each other. What will the magnitude of the force be if the distance between the particles is reduced to one-third of the original separation
411,403 views
9 votes
9 votes
Two charged particles exert an electric force of 27 N on each other. What will the magnitude of the force be if the distance between the particles is reduced to one-third of the original separation

User Logancautrell
by
2.6k points

1 Answer

24 votes
24 votes

Answer:

243 N

Step-by-step explanation:

The formula for electromagnetic force is F= Kq1q2/r^2

where r is the distance between the charges, if the distance between the charges is reduced by 1/3 then F will increase by 9 [(1/3r)^2 becomes 1/9r which is 9F] so 27*9 is 243N

User WolfiG
by
2.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

Other Questions

Determjne the density of liquid whose relative density is 1.25 given that the density is 1000kgm-3​
After a light turns green , Lesly accelerates to 120 km/hr over 100 meters . What is her acceleration in m/s^2
If a constant fotce of 490 newtons is applied to an object and it proceeds to accelerate in the opposjte direction at 9.8 meters per second, every second, what is its mass?
How can I solve the following? In (Figure 1), let V = 15.0 V and C1=C2=C3= 24.2 μF. Part A: How much energy is stored in the capacitor network as shown in (Figure 1)? Part B: How much energy would be stored
1. if i start with 48 ml of water in a graduated cylinder, after submerging an object the water level rises to 63 ml, what is the volume of the object. 2. if i start with 36 ml of water in a graduated
Link Copied!