Answer:
-√(1 - 2x) + C
Explanation:
1/√(1-2x)
We want to integrate it. Thus;
∫1/√(1 - 2x) dx
Let u = 1 - 2x
Thus;
du/dx = -2
Thus, dx = -½du
Thus,we now have;
-½∫1/√(u) du
By application of power rule, we will now have;
-½∫1/√(u) du = -√(u) + C
Plugging in the value of u, we will have;
-√(1 - 2x) + C