Question

3. How many moles are present in 100 g of Ca(NO3)2?
PLEASEEE HELP ASAPP

Answer 1

0.609 moles

Step-by-step explanation:

mass in g ÷ atomic mass = moles

Ca(NO₃)₂ = 1 Ca 40.078 amu

2 N 28.0134 amu

+ 6 O 95.994 amu

____________________

164.0854 amu

100 g ÷ 164.0854 amu = 0.609 moles

three significant digits

Answer 2

0Answer: 0.6094

Step-by-step explanation:

no of moles = mass / molar mass = 100/164.088= 0.6094 mole