Question

What is the magnitude of the electric field at a point 0.0055 m from a 0.0025

C charge?
kg
Use E = and k=9.00 x 10 N.m²/C2.
O A. 7.4 x 1011 N
O B. 2.0 x 1010 N
O C. 4.1 x 10°N
OD. 7.9 x 1012 N

Answer 1

Step-by-step explanation:

The equation for the electric field is

`E=(kQ)/(r^2)` so filling in:

`E=(9.00*10^9(.0025))/((.0055)^2)` which in the end gives you

E = 7.4 × 10¹¹, choice A