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4x2 + x - 3




1 Answer

9 votes

Answer:


\boxed{\textsf{ The roots of the quadratic equation is \textbf{ (-4) and 3 }.}}

Explanation:

A quadratic equation is given to us . Here we aren't given what to do with it. So , lets find out the roots of the equation . The given quadratic equation is :-


\sf\implies 4x^2+x-3 =0

Now with respect to Standard form ax²+bx + c . The roots of the equation can be find out by the quadratic formula also known as " Shreedharyacharya's Formula " .

Quadratic Formula :-


\boxed{\boxed{\sf x =(-b\pm √(b^2-4ac))/(2a)}}

Now with respect to Standard Form we have ,

• a = 4 •b = 1 •c = (-3)

Put on the respective values :-


\sf\implies x = (-b\pm √(b^2-4ac))/(2a) \\\\\sf\implies x =(-1\pm√(1^2-4(1)(-3)))/(2(1))\\\\\sf\implies x =(-1\pm √(1+48))/(2)\\\\\sf\implies x =(-1\pm √(49))/(2)\\\\\sf\implies x = (-1\pm 7 )/(2)\\\\\sf\implies x =(-1-7)/(2),(-1+7)/(2)\\\\\sf\implies x =(-8)/(2),(6)/(2)\\\\\sf\implies \boxed{\pink{\sf x = (-4) , 3 }}

User Bryan Menard
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