Question

calculate number of water molecules and number of oxygen and hydrogen atom in a drop of water containing 0.05 mole of water ​

Answer 1

Answer:
`0.301* 10^(23)` molecules of water

`0.6023* 10^(23)` atoms of hydrogen

`0.301* 10^(23)` atoms of oxygen

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

1 mole of water
`(H_2O)` contains =
`6.023* 10^(23)` molecules of water

Thus 0.05 moles of water
`(H_2O)` contain =
`(6.023* 10^(23))/(1)* 0.05=0.301* 10^(23)` molecules of water

Now , 1 molecule of water contains= 2 atoms of hydrogen

`0.301* 10^(23)` molecules of water contain =
`(2)/(1)* 0.301* 10^(23)=0.6023* 10^(23)` atoms of hydrogen

Now , 1 molecule of water contains = 1 atom of oxygen

`0.301* 10^(23)` molecules of water contain =
`(1)/(1)* 0.301* 10^(23)=0.301* 10^(23)` atoms of oxygen