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22 votes
Solve the simultaneous equations by substitution
8x – 3y = 5
3y = 2x + 1

User Kraiz
by
7.2k points

2 Answers

12 votes

Answer:

(1, 1 )

Explanation:

Given the 2 equations

8x - 3y = 5 → (1)

3y = 2x + 1 → (2)

Substitute y = 2x + 1 into (1)

8x - (2x + 1) = 5

8x - 2x - 1 = 5

6x - 1 = 5 ( add 1 to both sides )

6x = 6 ( divide both sides by 6 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for y

Substituting into (2)

3y = 2(1) + 1 = 2 + 1 = 3 ( divide both sides by 3 )

y = 1

solution is (1, 1 )

User TheDoomDestroyer
by
7.6k points
4 votes

Answer:

x = 1

y = 1

Explanation:

this should be your answer

Solve the simultaneous equations by substitution 8x – 3y = 5 3y = 2x + 1-example-1
User Nonsensickle
by
6.2k points
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