○=> Solution (6) :
Ratio of two numbers = 2:3
The larger number = 6
Let the smaller number be x.
Which means :
![=\tt 2 : 3 \: = \: x : 6](https://img.qammunity.org/2022/formulas/mathematics/college/bjjh3f389atn2l0s7frmwr6f22hr4pz9bg.png)
![= \tt (2)/(3) = (x)/(6)](https://img.qammunity.org/2022/formulas/mathematics/college/dt3jtnof2prmtq5bdq3cotwpmybdq5m6h3.png)
![=\tt 2 * 6 = 3 * x](https://img.qammunity.org/2022/formulas/mathematics/college/14m6djefepr5zhuf83sq59l9gh9avn9ud8.png)
![=\tt 12 = 3x](https://img.qammunity.org/2022/formulas/mathematics/college/a7vufc7rfiyrrm99cbjfz9x1qrb5yuxv8x.png)
![=\tt x = (12)/(3)](https://img.qammunity.org/2022/formulas/mathematics/college/p08m8aesv8pae3zf3vt62eosv14uw3niqf.png)
![\hookrightarrow\color{plum}\tt \: x = 4](https://img.qammunity.org/2022/formulas/mathematics/college/a1g6k783eher2usspqziv33v1oyqmtqprr.png)
▪︎Therefore, the smaller number = 4
○=> Solution (7) :
36 compared to 6 =
![\tt (36)/(6)](https://img.qammunity.org/2022/formulas/mathematics/college/vq384tec0in6w4pbunai3j4a1rwlt58t9t.png)
Let the number be x.
Which means :
![= \tt (36)/(6) = (x)/(3)](https://img.qammunity.org/2022/formulas/mathematics/college/9s04g3ferorgftnn9fr2snjx1d5fsl8nv4.png)
![=\tt (36 / 2)/(6 / 2) = (x)/(3)](https://img.qammunity.org/2022/formulas/mathematics/college/4r7zrhzpv91r8o9fkkjv04akz445czspov.png)
![=\tt (36)/(6) = (18)/(3)](https://img.qammunity.org/2022/formulas/mathematics/college/cggstavg58bh6hmis4dxqdu0a36y8foqlw.png)
▪︎Therefore, the fractional number
is equal to
.
○=> Solution (8) :
Number of Rose's for 24 red Rose's = 6
This can be written in a ratio as 24:6
Number of roses = 8
Let the number of red roses for these roses be x.
Which means :
![=\tt (24)/(6) = (x)/(8)](https://img.qammunity.org/2022/formulas/mathematics/college/m1k3x3a9w0ekock55tg296lxhdgvbodwco.png)
![=\tt 24 * 8 = 6 * x](https://img.qammunity.org/2022/formulas/mathematics/college/dwot7gs8kzwfu6dl19yddcovnc1kfw8mma.png)
![=\tt 192 = 6x](https://img.qammunity.org/2022/formulas/mathematics/college/4k2d3qrd987a27ylyvn5bir9nrq6q53sep.png)
![=\tt x = (192)/(6)](https://img.qammunity.org/2022/formulas/mathematics/college/7wohid858rdzh72i85uqmf8x5hj5xji4f0.png)
![\hookrightarrow \color{plum}\tt x = 32](https://img.qammunity.org/2022/formulas/mathematics/college/80foqlcju1down4fi92y2p5ldcy8b3l3y5.png)
▪︎Therefore, 32 red roses are there if there are 8 roses.
○=> Solution (9) :
Number of children for 2 adults = 7
This can be written in a ratio as 7:2
Number of children in the plaza = 21
Let the number of adults be x.
Which means :
![= \tt (7)/(2) = (21)/(x)](https://img.qammunity.org/2022/formulas/mathematics/college/3431th25wa52ml2xuvup3y55g5lcy7pb2h.png)
![=\tt7 * x = 2 * 21](https://img.qammunity.org/2022/formulas/mathematics/college/xnk0nrvu8yfdxwwbtg3xvk9438xu1axqes.png)
![=\tt 7x = 42](https://img.qammunity.org/2022/formulas/mathematics/college/adk5krg3ay9f3kfgynrglm90am2pexynj5.png)
![=\tt x = (42)/(7)](https://img.qammunity.org/2022/formulas/mathematics/college/s4t17ietp30wn6d65acnko1dkd36ffiph0.png)
![\hookrightarrow \color{plum}\tt \: x = 6](https://img.qammunity.org/2022/formulas/mathematics/college/x6hy5pohdoqyo8f0vse2dc2emj3003vxua.png)
▪︎Therefore, 6 adults were there in the plaza.
○=> Solution (10) :
Cost of 12 pencils = P60
Cost of 1 pencil :
![= \tt (60)/(12)](https://img.qammunity.org/2022/formulas/mathematics/college/fe3s7laee84hbaz0ycx3i2pdk7j2f3t6yc.png)
![=\tt P5](https://img.qammunity.org/2022/formulas/mathematics/college/7iuizmq9gggw4re5geqq21w0y9ofs1uson.png)
Thus, the cost of one pencil = P5
Cost of 25 pencils :
= Cost of one pencil × 25
![=\tt 5 * 25](https://img.qammunity.org/2022/formulas/mathematics/college/yjew9aifsh3mp01i36atihs6dd6st6xbi9.png)
![\color{plum}=\tt \: P \: 125](https://img.qammunity.org/2022/formulas/mathematics/college/h1pkoic1bss7yzg79a9t53c2tuh9pyz09o.png)
▪︎Therefore, the cost of 25 pencils = P125