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Please help!!! SEE PICTURE
PRECALC TRIG

Please help!!! SEE PICTURE PRECALC TRIG-example-1
User Ababuji
by
4.4k points

1 Answer

9 votes

Answer:

131.41 degrees

Explanation:

Given the equation

5(sinθ+3) = sinθ+12

5sinθ+15 = sinθ+12

5sinθ-sinθ = 12 - 15

4sinθ = -3

sinθ = -3/4

θ = arcsin(-0.75)

θ = -48.59 degrees

Since sin is negative in the 3rd quadrant

α = 180 + θ

α = 180 - 48.59

α = 131.41degrees

Hence the required angle is 131.41 degrees

User MrPizzaFace
by
4.5k points